Intereting Posts

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The Function $f:\mathbb{R}^{2}\rightarrow \mathbb{R}^{2}$ defined by $f(r,\theta)=(r\cos\theta,r\sin\theta)$
Necessary and Sufficient Condition for $\phi(i) = g^i$ as a homomorphism – Fraleigh p. 135 13.55
Green's function of a bounded domain is strictly negative
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Why rationalize the denominator?
Non-associative version of a group satisfying these identities: $(xy)y^{-1}=y^{-1}(yx)=x$
Minkowski sum of two disks
Does the sum of reciprocals of primes converge?
Dimension of a splitting field of a cubic polynomial over $\mathbb{Q}$
Cardinal number subtraction
Show that $d'(x,y)=min${$1,d(x,y)$} induces the same topology as $d$
Proof that $E(X)<\infty$ entails $\lim_{n\to\infty}n\Pr(X\ge n) = 0$?
Prove that there exists $n\in\mathbb{N}$ such that $f^{(n)}$ has at least n+1 zeros on $(-1,1)$

The number $4494410$ has the property that when converted to base $16$ it is $44944A_{16}$, then if the $A$ is expanded to $10$ in the string we get back the original number.

$3883544142410_{10}=3883544E24A_{16}$ is another.

These numbers are in OEIS A187829. They come in blocks of $6$ or $10$, depending on whether the one’s digit in hex is $A-F$ or $0-9$.

- How do you prove a function is defined for a a certain set?
- How to simplify $\frac{\sqrt{4+h}-2}{h}$
- How to prove $(a-b)^3 + (b-c)^3 + (c-a)^3 -3(a-b)(b-c)(c-a) = 0$ without calculations
- Solve three equations with three unknowns
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I suspect the list is complete but have not proven it. The largest is $806123145829415507126939101294137128298625241370656314360169_{10}=\\806C3E58294F507C6939AC94D7C829862524D706563E360169_{16}$

If the number has $m$ hex digits and $n$ base $10$ digits, we must have $16^{m-1} \gt 10^{n-1}$ and $16^{m-2} \lt 10^{n-2}$ which leads the hunt to $m=6,n=7;\ m=11,n=13;\ m=16, n=19;\ m=50,n=60$ guided by the convergents of $\frac {\log 16}{\log 10}$.

We can view finding these numbers as finding solutions to the subset-sum problem, where each hex digit contributes the difference between its value in base $16$ and base $10$ (depending on how many base $16$ digits to the right are $A-F$ and counting the two base $10$ digits coming from one hex digit together). The sum then has to be zero.

My search program ran reasonably quickly even for the next convergent, $m=535, n=644$ and didn’t find any. I believe they just have too many ways to fail as the number gets long.

Can we prove that there are no more, or at least that there are no more with very high probability, in the sense of “proofs” of Goldbach that if the primes are “random” the chance of any large even number having no solution is very low?

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I can prove a very narrow form.

Let’s consider numbers of the form:

$(D_{n-1}D_{n-2}…..D_{2}D_{1}D_0)_{10} = (D_{n-1}D_{n-2}…..D_2[A..F])_{16}$.

Here 2 least significant digits in decimal representation change

to [A..F]. For these numbers, conditions that need to satisfy are,

$100*x + 10 = n$ ….(1)

$16*y + 10 = n$ ….(2)

So,

$y = 6.25*x$ ….(3)

Let’s assume,

$x_{10}$ is of form $….N_{k-1}N_{k-2}…..N_{2}N_{1}N_{0}$

or,

$x_{10} = ….+ (N_{k-1}10^{k-1}) + (N_{k-2}10^{k-2}) + ….+ (N_{2}10^2) + (N_{1}10^1) + N_{0}$

So,

$y_{10} = ….+ (N_{k-1}16^{k-1}) + (N_{k-2}16^{k-2}) + ….+ (N_{2}16^2) + (N_{1}16^1) + N_{0}$

Also from (3),

$y_{10} = 6.25(….+ (N_{k-1}10^{k-1}) + (N_{k-2}10^{k-2}) + ….+ (N_{2}10^2) + (N_{1}10^1) + N_{0})$

So,

$(….+ (N_{k-1}16^{k-1}) + (N_{k-2}16^{k-2}) + ….+ (N_{2}16^2)

+ (N_{1}16) + N_{0}) =

6.25(….+ (N_{k-1}10^{k-1}) + (N_{k-2}10^{k-2}) + ….+ (N_{2}10^2)

+ (N_{1}10^1) + N_{0})$

Using up to 6 digits for x,

$(1048576N_5 + 65536N_4 + 4096N_3 + 256N_2 + 16N_1 + N_0) =

(625000N_5 + 62500N_4 + 6250N_3 + 625N_2 + 62.5N_1 + 6.25N_0)$

or,

$42357600N_5 + 303600N_4 – 215400N_3 – 36900N_2 – 4650N_1 – 525N_0 = 0$

Value in Hex falls behind till N3 because initial modulus was 100 for decimal

and 16 for hex. But at and after N4, hex value overtakes decimal forever.

Only solution for N5 (and above) between 0 and 9 is 0. Also, there are no solutions possible less

than 5 digits for x in (1).

So essentially numbers of these forms are only 7-digits or 2 digits,

And only possible solutions are,

```
10-15
4494410-4494415
5660810-5660815
6784010-6784015
7950410-7950415
```

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