# projective cubic

I have some difficulties to prove that the image of the function $f:\,\mathbb P^1\longrightarrow\mathbb P^3$ such that
$$(u,v)\longmapsto (u^3,\,u^2v,\,uv^2,\,v^3)$$
is the algebraic projective set
$$V(XT-YZ,\, Y^2-XZ,\,Z^2-YT)$$
Clearly I have problem to prove that the algebraic projective set is contained in the image of $f$. In particular “solving brutally” the polynomial system I’m losing my mind in calculations, so I hope that there is a simpler method.

#### Solutions Collecting From Web of "projective cubic"

Every point of $V=V(XT-YZ,\, Y^2-XZ,\,Z^2-YT)$ is in at least one of the four standard copies of $\mathbb A^3$affine spaces covering $\mathbb P^3$. So check them successively. I’ll do the $T=1$ part.

When $T=1$, $V$ is given by $$x=yz, \: y^2=xz,\: z^2=y$$
But then a point $(x,y,z)=[x:y:z:1] \in V$ satisfying these equations is simply the image under $f$ of $[u:v]=[z:1]\in \mathbb P^1$, since the first and third displayed equations for $V$ immediately imply that $x=yz=z^2.z=z^3$