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Good-morning Math Exchange (and good evening to some!)

I have a very basic question that is confusing me.

However, does this mean that $\sqrt {a^2} = +2$ **and**$-2$ or does it mean:

$\sqrt {a^2} = +2$ **OR**$-2$

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Any help would be greatly appreciated. Thanks in advance and enjoy the rest of your day đź™‚

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But the truth being that the squarte root function is always associated with absolute value function. That is

$\sqrt {a^2} = \vert a \vert $

This is very very important to remember and be careful while using the $ \sqrt{}

$ .

Note that if it is $ {(a^{2}})^{\frac{1}{2}} $ then we get answer as $\pm a $ but note that $\sqrt {a^2} = \vert a \vert $

Absoulte value is associated as **OR**

$\vert a \vert$ = $a$ OR $-a$

And is not used as a variable cant have two values at the same time !!

Even though quite a bit has been said already, i wanted to add something.

The numbers which you normally use in school (-1, $\frac{2}{3}$, $ \pi$, etcetera) are called the *real numbers*. The set of real numbers is denoted by $\mathbb{R}$.

Now the square root of any number $b$ is normally considered to be any number $x$ that satisfies $x^2 = b$, or equivalently $x^2 – b = 0$.

As you pointed out, there are normally two solutions to this, so two values for $x$ will do the trick. However, working in $\mathbb{R}$ this situation is remedied by adopting the convention that the square root of $b$ will be *the positive* number $x$ that satisfies $x^2 – b=0$. So indeed, when $b= a^2$, we get

$$

\sqrt{a^2} = |a|.

$$

So with this convention, the solutions to $x^2 – b=0$ become $x=\sqrt{b}$ and $x = -\sqrt{b}$. It is very important to note that this is merely a convention.

Even more: there are more sets of numbers we could work in, where this trick will not work! If we pass from the real numbers $\mathbb{R}$ to the so called *complex numbers*, denoted $\mathbb{C}$ (check wikipedia), we lose this! In this set of numbers, the notion of a positive number does not make sense, and it is in fact impossible to define a square root function in a nice way on the whole of $\mathbb{C}$ (if you want to know more about this, ask google).

In general there are many more things that i call “sets of numbers” now, in mathematics they are called “fields”. In all of them, the square root notion makes sense, as in solving the solution to $x^2 – b=0$. However, the nice $\sqrt{{}}$ function as we have it in $\mathbb{R}$ is rarely found in other fields.

Hope this context was interesting to you.

$\sqrt{\mathrm{a}^{2}}=|a|$= +a OR -a.Remember here OR is used.AND is not used as a function cannot have two values at same time.

The usual convention is that the square root sign gives the positive square root. When the negative/both is/are required, use the minus/plusminus sign.

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